Cuba, New York

Cuba, New York
Town
Town center along Genesee Street
Cuba
Location of Cuba in New York
Cuba
Cuba (the United States)
Coordinates: 42°13′04″N 78°16′31″W / 42.21778°N 78.27528°W / 42.21778; -78.27528
CountryUnited States
StateNew York
CountyAllegany
Area
[1]
 • Total35.80 sq mi (92.73 km2)
 • Land35.10 sq mi (90.91 km2)
 • Water0.70 sq mi (1.82 km2)
Population
 (2020)[2]
 • Total3,126
 • Density89.06/sq mi (34.39/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code36-003-19367
Websitehttps://www.cubany.org/

Cuba is a town in Allegany County, New York, United States. As of the 2020 United States Census, the total population was 3,126.[2]

References

  1. ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 7, 2024.
  2. ↑ 2.0 2.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Cuba town, Allegany County, New York". United States Census Bureau. Retrieved March 7, 2024.
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