Jefferson, Ohio

Jefferson, Ohio
Village
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Coordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°W / 41.73861; -80.75694
CountryUnited States
StateOhio
CountyAshtabula
Area
[1]
 • Total2.54 sq mi (6.57 km2)
 • Land2.54 sq mi (6.57 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
[2]
961 ft (293 m)
Population
 (2020)[3]
 • Total3,226
 • Density1,271.58/sq mi (491.04/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
44047
Area code440
FIPS code39-38500[4]
GNIS feature ID1042061[2]
Websitehttps://jeffersonohio.gov/

Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.[3] It is the county seat of Ashtabula County.[5]

References

  1. ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. ↑ 2.0 2.1 U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
  3. ↑ 3.0 3.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson village, Ohio". United States Census Bureau. Retrieved March 16, 2024.
  4. ↑ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  5. ↑ National Association of Counties. "NACo County Explorer". Retrieved March 15, 2024.


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